-
Notifications
You must be signed in to change notification settings - Fork 6
Expand file tree
/
Copy path102. Binary Tree Level Order Traversal.js
More file actions
68 lines (58 loc) · 1.22 KB
/
102. Binary Tree Level Order Traversal.js
File metadata and controls
68 lines (58 loc) · 1.22 KB
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
/**
* Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level).
* For example:
* Given binary tree [3,9,20,null,null,15,7],
* [
* [3],
* [9,20],
* [15,7],
* ]
*/
/**
* Hints:
* Maintain count for current level nodes
* Push valid next level nodes to a queue and count
* When current level count = 0, move to the next level
*/
/**
* Definition for a binary tree node.
* function TreeNode(val) {
* this.val = val;
* this.left = this.right = null;
* }
*/
/**
* @param {TreeNode} root
* @return {number[][]}
*/
var levelOrder = function(root) {
const ro = [];
if (root === null){
return ro;
}
const queue = [];
let temp = [];
let currentLevelCount = 1;
let nextLevelCount = 0;
queue.push(root);
while (queue.length > 0) {
const node = queue.shift();
temp.push(node.val);
currentLevelCount--;
if (node.left) {
queue.push(node.left);
nextLevelCount++;
}
if (node.right) {
queue.push(node.right);
nextLevelCount++;
}
if (currentLevelCount === 0) {
ro.push(temp);
temp = [];
currentLevelCount = nextLevelCount;
nextLevelCount = 0;
}
}
return ro;
};