# Function std::mem::align_of_val_raw

const: unstable · source ·

    pub unsafe fn align_of_val_raw<T>(val: *const T) -> usizewhere
        T: ?Sized,

🔬This is a nightly-only experimental API. (`layout_for_ptr` #69835)
Expand description

Returns the ABI-required minimum alignment of the type of the value that `val` points to in bytes.

Every reference to a value of the type `T` must be a multiple of this number.

## Safety

This function is only safe to call if the following conditions hold:

- If `T` is `Sized`, this function is always safe to call.
- If the unsized tail of `T` is:
  - a slice, then the length of the slice tail must be an initialized integer, and the size of the entire value (dynamic tail length + statically sized prefix) must fit in `isize`.
  - a trait object, then the vtable part of the pointer must point to a valid vtable acquired by an unsizing coercion, and the size of the entire value (dynamic tail length + statically sized prefix) must fit in `isize`.
  - an (unstable) extern type, then this function is always safe to call, but may panic or otherwise return the wrong value, as the extern type’s layout is not known. This is the same behavior as `align_of_val` on a reference to a type with an extern type tail.
  - otherwise, it is conservatively not allowed to call this function.

## Examples

    #![feature(layout_for_ptr)]
    use std::mem;

    assert_eq!(4, unsafe { mem::align_of_val_raw(&5i32) });

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