# Function std::mem::transmute_copy

1.0.0 (const: 1.74.0) · source ·

    pub const unsafe fn transmute_copy<Src, Dst>(src: &Src) -> Dst

Expand description

Interprets `src` as having type `&Dst`, and then reads `src` without moving the contained value.

This function will unsafely assume the pointer `src` is valid for `size_of::<Dst>` bytes by transmuting `&Src` to `&Dst` and then reading the `&Dst` (except that this is done in a way that is correct even when `&Dst` has stricter alignment requirements than `&Src`). It will also unsafely create a copy of the contained value instead of moving out of `src`.

It is not a compile-time error if `Src` and `Dst` have different sizes, but it is highly encouraged to only invoke this function where `Src` and `Dst` have the same size. This function triggers undefined behavior if `Dst` is larger than `Src`.

## Examples

    use std::mem;

    #[repr(packed)]
    struct Foo {
        bar: u8,
    }

    let foo_array = [10u8];

    unsafe {
        // Copy the data from 'foo_array' and treat it as a 'Foo'
        let mut foo_struct: Foo = mem::transmute_copy(&foo_array);
        assert_eq!(foo_struct.bar, 10);

        // Modify the copied data
        foo_struct.bar = 20;
        assert_eq!(foo_struct.bar, 20);
    }

    // The contents of 'foo_array' should not have changed
    assert_eq!(foo_array, [10]);

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