Adapted complex exp() function so that it can handle inf and nan arguments as well#104
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Could you please add that reference link as a comment in the test? |
…webpage from which the test values were taken.
OK. Done. |
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A gentle reminder... |
src/lib.rs
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| // formula: e^(a + bi) = e^a (cos(b) + i*sin(b)) = from_polar(e^a, b) | ||
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| // Treat the corner cases +∞, -∞, and NaN | ||
| let mut im = self.im; |
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I think this may be easier to follow if we unpack both parts, and then use them directly throughout.
| let mut im = self.im; | |
| let Complex { re, mut im } = self; |
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Thanks for the suggestion, I just implemented, tested, and git-pushed it.
src/lib.rs
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| if self.re.is_infinite() { | ||
| if self.re < T::zero() { | ||
| if !self.im.is_finite() { | ||
| im = T::one(); |
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Where does this 1.0 come from -- is that an arbitrary choice?
I think the result will be 0+0i, so why not just return that?
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It's indeed an arbitrary choice (following the clang C++ implementation). I agree that it would be simpler to just return 0+0i, so I just implemented, tested, and git-pushed that.
src/lib.rs
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| // Compare the imaginary parts | ||
| if a.im.is_finite() { | ||
| if b.im.is_finite() { | ||
| close = (a.im == b.im) || (a.im - b.im).abs() < tol; |
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We shouldn't lose the re comparison.
| close = (a.im == b.im) || (a.im - b.im).abs() < tol; | |
| close &= (a.im == b.im) || (a.im - b.im).abs() < tol; |
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Aargh, sorry about that... None of the unit tests caught this. I just fixed the bug.
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Yeah, "Who tests the tester?" It could just return true, and the unit tests would pass. :)
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bors r+ |
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Build succeeded: |
2 participants
Why this PR?
The current version of the complex exp() function is not able to handle arguments that contain +/- inf or NaN in their real or imaginary part. This impacts other complex functions that use the exp() function.
For example, for the most widely used implementation of the complex Faddeeva function
w(), the currentexp()implementation leads tow(1e160 - 1e159*i) = NaN + NaN *i, while the correct value is-5.586035480670854e-162 + 5.5860354806708545e-161 * i. The underlying reason is that the currentexp()implementation erroneously returnsexp(-inf + inf *i) = NaN + Nan *iinstead of the correct0 + 0*i.Cf also issue #103.
Contents of this PR
<complex>C++ header that comes with clang++.close_naninf()andclose_naninf_to_tol()as the existing functionsclose()andclose_to_tol()are not able to deal with inf and nan.